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This commit is contained in:
3
159-2.py
3
159-2.py
@@ -1,6 +1,7 @@
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import math
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import matplotlib.pyplot as plt
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#把原函数换成题干的形式########################
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def fx(x):
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return math.exp(x)-math.sin(x)
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@@ -25,7 +26,7 @@ def DrawGraph(a, b, stepper):
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plt.show()
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return x, y
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#把范围改成题干的形式#######################
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if __name__ == "__main__":
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a = -2*math.pi
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b = math.pi
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7
159-5.py
7
159-5.py
@@ -1,6 +1,6 @@
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import math
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#原函数和导数改成题干的形式#####################
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def f1(x):
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return x**2 + 10*math.cos(x)
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@@ -17,12 +17,14 @@ def df2(x):
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# 牛顿方法求解方程
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def NewtonSolve(fx, dfx, x0, err, N0):
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count = 0
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print(f"k={count}, x0={x0}")
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x1 = x0 + 1 + err
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while abs(x1 - x0) > err or abs(fx(x1)) > err: # 添加条件修正根误差太大的问题
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if abs(dfx(x1)) < 1e-10:
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return None, 0
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x1 = x0 - fx(x0) / dfx(x0)
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count += 1
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print(f"k={count}, x{count}={x1},x1-x0={abs(x1-x0)}")
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if count > N0:
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return None, -1
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x0 = x1
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@@ -41,6 +43,7 @@ if __name__ == "__main__":
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err = 1e-5
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N0 = 100
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#把初始值换成题干形式###############
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x0 = 1.6
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result,status = NewtonSolve(f1, df1, x0, err,N0)
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if status == 1:
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@@ -51,7 +54,7 @@ if __name__ == "__main__":
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print("f1导数为0,无法收敛")
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x0 = FindRootZone(f2, -5, 5, 0.01)
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x0 = FindRootZone(f2, -5, 5, 0.01) # 查找f2的根区间与步长
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result, status = NewtonSolve(f2, df2, x0, err,N0)
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if status == 1:
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print(f"f2收敛 解为: {result}")
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6
159-6.py
6
159-6.py
@@ -1,6 +1,6 @@
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import math
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#把函数改成题干的形式#####################
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def f(x):
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return x**2 - 30
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@@ -10,12 +10,14 @@ def df(x):
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# 牛顿方法求解方程
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def NewtonSolve(fx, dfx, x0, err, N0):
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count = 0
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print(f"k={count}, x0={x0}")
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x1 = x0 + 1 + err
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while abs(x1 - x0) > err or abs(fx(x1)) > err: # 添加条件修正根误差太大的问题
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if abs(dfx(x1)) < 1e-10:
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return None, 0
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x1 = x0 - fx(x0) / dfx(x0)
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count += 1
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print(f"k={count}, x{count}={x1},x1-x0={abs(x1-x0)}")
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if count > N0:
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return None, -1
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x0 = x1
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@@ -34,6 +36,6 @@ if __name__ == "__main__":
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err = 1e-4
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N0 = 100
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x0 = FindRootZone(f, 5, 6, 0.01)
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x0 = FindRootZone(f, 5, 6, 0.1) # 查找f的根的区间与步长,改成题干对应的范围
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result,status = NewtonSolve(f, df, x0, err,N0)
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print(f"sqrt(30) = {result:.3f}")
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@@ -17,11 +17,11 @@ def SecantSolve(fx, x0, x1, err=1e-10, N0=100):
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x1 = x2
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return x2,1
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#把精度要求改成题干要求的##########################
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if __name__ == "__main__":
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err = 1e-5
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N0 = 100
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##把初始函数和初始值改成题干要求的##########################
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x0 = 0.3
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x1 = 0.4
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fx = lambda x: x**4 - 3*x + 1
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