Files
CalWay_Python/69-5.py
2025-06-13 22:24:52 +08:00

121 lines
3.7 KiB
Python

# 追赶法
def ZGsolve(A,b):
n = len(b)
beta = [0]*n
for i in range(n):
if i == 0:
beta[i] = A[i][2] / A[i][1]
else:
beta[i] = A[i][2] / (A[i][1] - A[i][0]*beta[i-1])
for i in range(n):
if i == 0:
b[i] = b[i] / A[i][1]
else:
b[i] = (b[i] - A[i][0]*b[i-1]) / (A[i][1] - A[i][0]*beta[i-1])
for i in range(n-2,-1,-1):
b[i] = b[i] - beta[i]*b[i+1]
return b
# 获取相邻点的差分
def GetDList(list_r):
result = []
for i in range(1,len(list_r)):
result.append(list_r[i] - list_r[i-1])
return result
# 获取相邻点的差商
def GetDQList(list_x, list_y):
result = []
for i in range(1,len(list_y)):
result.append((list_y[i] - list_y[i-1]) / (list_x[i] - list_x[i-1]))
return result
# 三次样条插值
def CubicSplineInterpolation(list_x,list_y,boundary_type,a1,a2):
list_h = GetDList(list_x)
print("h:", list_h)
list_dqxy = GetDQList(list_x, list_y)
print("f[xi,xi+1]:", list_dqxy)
list_mu = [list_h[i]/(list_h[i]+list_h[i+1]) for i in range(len(list_h)-1)]
print("miu:", list_mu)
list_lamda = [1-i for i in list_mu]
print("lambda:", list_lamda)
list_g = [6*(list_dqxy[i+1]-list_dqxy[i])/(list_h[i+1]+list_h[i]) for i in range(len(list_h)-1)]
A = []
b = []
M = []
copy_b = []
if boundary_type == 0: # 自然边界条件
a1 = 0
a2 = 0
A.append([0,2,list_lamda[0]])
b.append(list_g[0]-list_mu[0]*a1)
for i in range(1,len(list_g)-1):
A.append([list_mu[i],2,list_lamda[i]])
b.append(list_g[i])
A.append([list_mu[-1],2,0])
b.append(list_g[-1]-list_lamda[-1]*a2)
copy_b = b.copy()
print("g1~gn-1:", list_g)
M = ZGsolve(A,b)
M = [a1] + M + [a2]
elif boundary_type == 1: # 一阶导数边界条件
A.append([0,2,1])
b.append(6/list_h[0]*(list_dqxy[1]-a1))
for i in range(len(list_g)):
A.append([list_mu[i],2,list_lamda[i]])
b.append(list_g[i])
A.append([1,2,0])
b.append(6/list_h[-1]*(a2-list_dqxy[-1]))
copy_b = b.copy()
print("g0~gn:", copy_b)
M = ZGsolve(A,b)
elif boundary_type == 2: # 二阶导数边界条件
A.append([0,2,list_lamda[0]])
b.append(list_g[0]-list_mu[0]*a1)
for i in range(1,len(list_g)-1):
A.append([list_mu[i],2,list_lamda[i]])
b.append(list_g[i])
A.append([list_mu[-1],2,0])
b.append(list_g[-1]-list_lamda[-1]*a2)
copy_b = b.copy()
print("g1~gn-1:", list_g)
M = ZGsolve(A,b)
M = [a1] + M + [a2]
print("A:", A)
print("b:", copy_b)
print("M:", M)
return M,list_h
# 打印矩阵
def PrintResult(M,list_h,list_x,list_y):
for i in range(len(list_h)):
k1 = (M[i+1]-M[i])/6/list_h[i]
k2 = (M[i]*list_x[i+1]-M[i+1]*list_x[i])/2/list_h[i]
k3 = (3*M[i+1]*list_x[i]**2-3*M[i]*list_x[i+1]**2-6*list_y[i]+M[i]*list_h[i]**2+6*list_y[i+1]-M[i+1]*list_h[i]**2)/6/list_h[i]
k4 = (M[i]*list_x[i+1]**3-M[i+1]*list_x[i]**3+6*list_y[i]*list_x[i+1]-M[i]*list_h[i]**2*list_x[i+1]-6*list_y[i+1]*list_x[i]+M[i+1]*list_h[i]**2*list_x[i])/6/list_h[i]
print("S(x)=%.6f*x^3+%.6f*x^2+%6f*x+%6f"%(k1,k2,k3,k4),"x=[%.6f,%.6f]"%(list_x[i],list_x[i+1]))
#将x,y换成题干的数值###########################################
if __name__ == "__main__":
x = [0,1,2,3]
y = [0,0,0,0]
M,list_h = CubicSplineInterpolation(x,y,2,1,0)
print("二阶导数边界条件:")
PrintResult(M,list_h,x,y)
M,list_h = CubicSplineInterpolation(x,y,1,1,0)
print("一阶导数边界条件:")
PrintResult(M,list_h,x,y)