68 lines
2.0 KiB
Python
68 lines
2.0 KiB
Python
import math
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def fx(x):
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if x == 0:
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x = 1e-10 # Avoid division by zero #如果x能为0，注释掉这行##############
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pass
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return math.sin(x)/x #把函数改成题干的形式###################
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# 龙贝格方法 积分
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def Romberg(a, b, err):
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table = [[],[],[],[]]
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t00 = (b-a)*(fx(a)+fx(b))/2
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table[0].append(t00)
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print(f"t0(0)={t00}")
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t01 = t10 = t11 = t20 = t21 = t30 = t31 = 0
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k = 1
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while True:
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tmp = 0
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for i in range(1, 2**(k-1)+1):
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tmp += fx(a + (b-a)*(2*i-1)/(2**k))
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t01 = t00/2+(b-a)*tmp/(2**k)
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print(f"t0({k})={t01}")
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table[0].append(t01)
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if k>1:
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t11 = (4*t01-t00)/3
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print(f"t1({k-1})={t11}")
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table[1].append(t11)
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if k>2:
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t21 = (16*t11-t10)/15
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print(f"t2({k-2})={t21}")
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table[2].append(t21)
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if k>3:
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t31 = (64*t21-t20)/63
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print(f"t3({k-3})={t31}")
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table[3].append(t31)
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if abs(t31-t30) < err:
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break
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t30 = t31
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else:
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t30 = (64*t21-t20)/63
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print(f"t3(0)={t30}")
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table[3].append(t30)
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t20 = t21
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else:
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t20 = (16*t11-t10)/15
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print(f"t2(0)={t20}")
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table[2].append(t20)
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t10 = t11
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else:
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t10 = (4*t01-t00)/3
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print(f"t1(0)={t10}")
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table[1].append(t10)
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t00 = t01
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k += 1
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print("Romberg table:")
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for i in range(len(table)):
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print(f"t{i}: {table[i]}")
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return t31, k
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# 把范围ab与精度换成题干的############
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if __name__ == "__main__":
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a = 0
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b = 1
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err = 0.5e-6 #把精度要求改成题干的##################
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result, k = Romberg(a, b, err)
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print(f"Result: {result}, k={k}")
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