隐式
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61
按方法整理/常微分方程-阿达姆斯隐式方法.py
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61
按方法整理/常微分方程-阿达姆斯隐式方法.py
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import math
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def AdamusImplicitly(k,first_ys,x0,y0,h,xk,fxy,fx_real):
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betas = [
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[1],
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[1/2, 1/2],
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[5/12, 8/12, -1/12],
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[9/24, 19/24, -5/24, 1/24],
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[251/720, 646/720, -261/720, 106/720, -19/720],
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[475/1440, 1427/1440, -798/1440, 482/1440, -173/1440, 27/1440]
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]
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result = []
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if k<0 or k >= len(betas):
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print("k超出范围")
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return None
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if len(first_ys) != k:
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print("first_ys(前几个y的值)与k长度不匹配")
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return None
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fxys = [fxy(x0+i*h, first_ys[i]) for i in range(k)]
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for i in range(k):
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result.append((x0 + i * h, first_ys[i]))
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x1 = x0 + h*k
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y0 = first_ys[k-1]
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while x1 < xk:
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y1_t = y0
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y1 = y0 + 1
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for j in range(1000):
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y1 = y0 + h * sum(betas[k][i+1] * fxys[k-i-1] for i in range(k))+ h * betas[k][0] * fxy(x1, y1_t)
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if abs(y1 - y1_t) < 1e-14:
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break
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y1_t = y1
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# y1 = y0 + delta_y
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print(f"x={x1}, y={y1}, real_y={fx_real(x1)}, abs(real_y-y)={abs(fx_real(x1) - y1)}")
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result.append((x1, y1))
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fxys.append(fxy(x1, y1))
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fxys.pop(0)
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y0 = y1
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x1 += h
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return result
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if __name__ == "__main__":
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# 定义初始值和参数#####################################################################################
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k = 3 # 阿达姆斯k步隐式方法,精度为k+1阶,最常用k=3,其他阶数我没试过 P255
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first_ys = [1, 0.904837418036, 0.818730753078] # 前几个y的值,可用龙格-库塔计算或者知道精确解自己算出来
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x0 = 0.0 # 初始x值
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y0 = 1.0 # 初始y值
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h = 0.1 # 步长
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xk = 1.0 # 最终x值
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fxy = lambda x, y: -y # 定义f(x,y)函数,dx/dy = f(x,y),导函数
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fx_real = lambda x: math.exp(-x) # 实际解函数,用于验证结果,如果不知道或者不用算误差,可以直接写个 lambda x: 0
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# 调用阿达姆斯隐式方法
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result = AdamusImplicitly(k, first_ys, x0, y0, h, xk, fxy, fx_real)
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print("计算结果看到有几.99999或者几.00000就自己四舍五入一下,有可能会多算一点,自己比较一下")
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if result:
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for xy in result:
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print(f"(x, y): {xy}")
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