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@@ -32,7 +32,7 @@ def SOR(A,b,x,w,err,N):
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if count > N:
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return None,count, 0
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#把矩阵改成题干的矩阵,b改成题干结果,err精度要求修改##########################
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if __name__ == "__main__":
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A = [
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[4,-1,0,-1,0,0],
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@@ -46,7 +46,7 @@ if __name__ == "__main__":
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x = [0,0, 0, 0, 0, 0]
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err = 1e-5
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#w换成题干要求的值###########################
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w = 1
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x1,k,sta = SOR(A, b, x, w, err, 100)
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print(f"w = {w}, 解为: {x1}, 迭代次数: {k}, 状态: {'收敛' if sta == 1 else '未收敛'}")
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